Question

(3 points) inverted king post 01

The truss shown is called a king-post truss. It is inverted, such that the structure lies below the plane of the supports. Find the reactions at the supports and the forces carried in each member when a force of FF = 14 kN is applied and the dimensions of the truss are given below.

a = 4.5 m
θ = 58 degrees
ϕ = 56 degrees

@ 000 BY NC SA 2013 Michael Swanbom

Designate members in compression with negative values, and members in tension with positive values.

RAhorizontal =

RAvertical =

RCvertical =

TAB =

TBC =

TCD =

TAD =

TBD =

be sure to include units with your answers

Answer 1

Sal? - F - 14kM4 .9 4.5m B: 58° • 56' a asino - Decond > 4.5 Bin (58') : sex Cos (57'). DC = 6.894m AB: a Cote 29.384m i BC BC-DC DC and be = 5.65 Im ها N EMA so cyx (AB + BC) = FXAB y : 4.151 km Eftso - Anzo] Efyco Ay & cya 14 Ay = 9.898 km] How considering Joint a FBC {fy so foc Cose = 40151 14.151km foc I foc - 7.423 KM Efxzo fsc = foc sind | foc = 6-154km J) 14KH Ноо «ку Фі— () {fyzo [fBD = 14 kH(( Ifx=0, this a 6.154km

How taking Joint (A) Efy so fAdsino = AY 9.849, fAD 3 1.614 KMC). Ax ZOM , Ays 9.849 km , cy4.151 kr TAB = 6:154KM ) , T Be = 6.154KMCC), Teos 7.923KM (T) TAD= 11-614 KH (T) TOD= 14 km(s)