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A 1.10 kg mass hangs from a spring of force constant 400 N/m . The mass...

A 1.10 kg mass hangs from a spring of force constant 400 N/m . The mass is then pulled down 13.0 cm from the equilibrium position and released. At the end of five complete cycles of vibration, the mass reaches only 10.0 cm from the equilibrium position.

Part A: How much mechanical energy is lost during these five cycles?
Part B: What percentage of the mechanical energy is lost during the five cycles?

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Answer #1

di 10 oocm UCone)-. О.sx(40ο) Χ (013)2:13:3 80 Joule 40.8%

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