Force, F = Pressure x area
Pressure, P = pgh = 1024 x 9.8 x 97 = 9.73 x 10^5 kg/m s^2
Force, F = 9.73 x 10^5 x 1.2 x 0.35 = 4.09 x 10^5 N
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Submarine crew escapes Due this Sunday, Jun 23 at 08:00 pm (EDT) Crew members attempt to...
Crew members attempt to escape from a damaged submarine 117 m below the surface.What force must be applied to a pop-out hatch, which is 0.846 m by 0.423 m, to push it out at that depth? Assume that the density of the ocean water is 1024 kg/m3 and the internal air pressure is at 1.00 atm.
US Help System Announcements PRINTER VERSION s BACK NEXT Chapter 14, Problem 017 Crew members attempt to escape from a damaged submarine 52.1 m below the surface. What force must be applied to a pop-out hatch, which is 0.866 m by 0.433 m, to push it out at that depth? Assume that the density of the ocean water is 1024 kg/m and the internal air pressure is at 1.00 atm. Number Units the tolerance is +/-2% Click If you would...
Please answer all questions and all parts. Please also provide the correct final units. Thanks! 1. Crew members attempt to escape from a damaged submarine 100m below the surface. What force must be applied to a pop-out hatch, which is 1.05m by 0.70m, to push it out at that depth? Assume that the density of the ocean water is 1025kg/m3? 2a. A car misses a turn, sinks into a shallow lake, coming to rest on its side with the door...