Question

Experiment I. 2. Build the DC Inverting Amplifier with RI-22K R2=100K For the lab, we can utilize the breadboard optimally by plugging the Op-Amp into the breadboard so that it straddles the gap between the top and bottom sections of the socket strip, which is shown in Fig. P.5 Output 741 +Input Fig. P.5. Op-Amp Positioning on Breadboard. 3. Sct the Power Source CHI and CH2 to 15 V a. Ensure the output is OFF before attaching the power supply to your Op-Amp b. Connect Vcc+ (pin 7) to the positive terminal of CHI (red cable) of the power supply. Connect the negative terminal (black cable) to ground at pin 3 c. Connect Vcc. (pin 4) to the negative terminal of CH2 (black cable) of the power supply. Connect the positive terminal (red cable) to ground. Set the Power Source 5-Volt of CH3 terminals to 1 V a. Ensure the output is OFF before attaching the power supply to your Op-Amp. b. Connect the negative terminal of CH3 to the ground. c. Connect the positive terminal to R1 which is then connected to Vs (pin 2) Turn on the power supply, measure the Vout of the Op-Amp using the DMM. Verify that the voltage gain (K) .Fill all the required calculated data (design), and measurements in Table P.3. 4. 5. 6. Change the original 1V input to 5V, what is Vour? Discuss any limitations you find in the analysis of this lab. Table P.3. Design and Verification of DC Inverting Op-Amps Design Measurement

I would like the values for the table

Answer 1

Measured values can be calculated only after the experiment.

Since it is an inverting amplifier, its design gain is given by, K= -R2/R1=-4.5454

Due to the virtual ground, V_N and V_P will be in the same potential. Since, V_P =0V, so V_N=0V.

	Design
VP	0V
VN	0V
Vin	1V
Vout	-4.5454V
K	-4.5454

We know that Vout=K.Vin

When the input is changed to 1V to 5V, the output voltage will supposed to be -22.7272V. But this is more than negative supply which is -15V. So the opamp will be in negative saturation. So V_out will be -15V.