Question

i have no idea how to do floating point comparison this is c programming

CHALLENGE 3.16.1: Floating-point comparison: Print Equal or Not equal Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is Equal 1 #include <stdio.h 2 #include <math.h> 4 int main(void)f 6 8 scanf("%lf", &targetValue); 1 test passed double targetValue; double sensorReading; All tests passed 9 canf("S1f", &sensorReading); 11 if (/* Your solution goes here */) { printf("Equal\n"); 13 14 else printf("Not equal\n"); 16 17 18 19 return 0 Run

Answer 1

Code Screenshots:

#include #include <stdio.h> <math.h> int main (void) [ double targetValue double sensorReading; scanf("%1f", scanf("slf", &targe tvalue); &sensorReading); //If the absolute difference of the //two values is less than 0.0001 then, //the value s are c nsidered to be cl。se en ugh if (fabs (targetValue - sensorReading) < 0.0001) t printf "Equaln" else printf("Not Equal\n"); return 0;

Sample Output:

О. 3333 0.33333333 Equal

Code To Copy:

#include <stdio.h>

#include <math.h>

int main(void){

double targetValue;

double sensorReading;

scanf("%lf", &targetValue);

scanf("%lf", &sensorReading);

//If the absolute difference of the

//two values is less than 0.0001 then,

//the values are considered to be close enough.

if(fabs(targetValue - sensorReading) < 0.0001){

printf("Equal\n");

}

else{

printf("Not Equal\n");

}

return 0;

}