Question

Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in an expression.
C++ please!

#include <stdio.h>

double FindMax(double num1, double num2) {
double maxVal;

// Note: if-else statements need not be understood to complete this activity
if (num1 > num2) { // if num1 is greater than num2,
maxVal = num1; // then num1 is the maxVal.
}
else { // Otherwise,
maxVal = num2; // num2 is the maxVal.
}

return maxVal;
}

int main(void) {
double numA;
double numB;
double numY;
double numZ;
double maxSum;

scanf("%lf", &numA);
scanf("%lf", &numB);
scanf("%lf", &numY);
scanf("%lf", &numZ);

/* Your solution goes here */

printf("maxSum is: %.1f\n", maxSum);

return 0;
}

Answer 1

#include <stdio.h>

double FindMax(double num1, double num2) {
    double maxVal;

// Note: if-else statements need not be understood to complete this activity
    if (num1 > num2) { // if num1 is greater than num2,
        maxVal = num1; // then num1 is the maxVal.
    } else { // Otherwise,
        maxVal = num2; // num2 is the maxVal.
    }

    return maxVal;
}

int main(void) {
    double numA;
    double numB;
    double numY;
    double numZ;
    double maxSum;

    scanf("%lf", &numA);
    scanf("%lf", &numB);
    scanf("%lf", &numY);
    scanf("%lf", &numZ);
    maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

    printf("maxSum is: %.1f\n", maxSum);

    return 0;
}