Question

2. Find to in the network below using loop analysis. 6k2 662 w 6 Ic + "6 Ib + 6 (Ia- Ic) = 0 In- Ia- SMA (IB - Ic) + 6Ib - GV + 6 (Ia - It) = 0 5 mA in 36ko 61B + 6 Ia=0 Ib - Ia = SMA 12 IB= 30mA IB= 2.5mA - Io

Answer 1

Solution .662 ic m A Supermesh mesh occurs when a current source 8 Contained between two essential meshes. * Applying Supermess Analysis +6+6Kizi G KLED-E) +6kºj = 0 6+6Klie-66) +6*4*6=ic) +6K) =0 6+6Kcia-ic) +okCEb-4c)+6**)=0 = 6kia +12K1-12K1C 2-670 = From the cruit เ:45 me i5-5mA+TQ +@ Substitute Eq @ En © = 6kia+12% (57+) -12kic= Cs:szno 18K€ + 60-12kic 5-6 camscanner

& Iskia lakic - - 66 x Again From mesh Analysis Gk + Gk - 5) +6k (% - Ca) = 0 - 6kia- 6k Üb +18k*c .= 0. --kia-6k C50+ lal) +18kić = 0 -12kia-30+18°C = 0 - 12kia'+istic = 30 + Solving 0 % 0 Z-4MA Q = -4.6MA p=5maria = 5MA=46MA is = 0.4m4 B8) 400A To = = 0.4mA -Thank You - Scalmed with CamScamien

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