Question

Find V. in the network in the figure using loop analysis. 6 ν(Ε) (14 mA 1 ΚΩ T + VO - –ΛΛΑ 2 ΚΩ 32 ΚΩ 31 ΚΩ ( 3 mA

Find V_o in the network in the figure using loop analysis.

Answer 1

Assume loop currents across each loop.

Write KVL equations.

Detailed solution is given below:

PAGE-01 a. Find Vo wing looh analysis GVA 2KRZ 1KR + Vo- (1) UMA 2KR {2kr 1kR & SMA meches. Asuming sol. Comesh four loops ou coment There are current) Sve o top + Vo- MEM 2KR 1kg 2KR} I ) 1kr | A IMA looke - ibritting KVL eque fou all the For Loop-1 6 - 2 I, + 2 Ig - 2 I t Iz=0. = 31, - 2 12 - I3 = 6 to For Look-3 - 2 Iz - Ist I, - IztI4=0. - 4 Iz = Iitly (2) cuwent sources are present Now we see that there are acroll Look 2 and Loon-4

PAGIE-02 When we come acrou a look having c ent source, we SUPERMESH But here supermuch in not posible. This i happening because in above wiant Lowent towice id not present between two looke but in pruent cacross conly one loop ② so we go for the look -2. It can be seen that I 2 = -4mA. In look-4, it can be seen that ly = - 3mA. Using the value of Iz & I4 wir 6 & ② , 3 I, - 2xl-4) - Iz = 6 = 341 - Iz = 6-8=8] - Iz = -2 From @ 4 Iz = I - 3 - I = 4 Iz + 3. 4 Putting the value of Il in @ 3 (453+3) - Iz=-2 + 12 Iz +9 I3 = -2 = 1113=-11 > Iz= - Ima Pulling the value of Iz un 4 I = 4X61) +8= - IMA I = - IMAL + Vo - moms 7 2K6 I From Ohme law, Vo = (I4 - Iz) x 2 kr. Vo = [3mA - (- 4A)]* 2KR Vo = IMAX 2KR Vo = 2 wolle