Question

2. (25 points) Later in the day, the frog and its lily pad were floating at rest, 21 cm in front of a 10 cm tall rock. The rock is perfectly flat on its top surface. The frog decides to jump onto the rock... Determine the velocity that the the frog must leave the lily pad with, in order to be moving horizontally when it lands on the rock. Hint: If you make a toolbor, it may help to keep the initial velocities as vox and Voy instead of using sin 9 or cos 0.

Answer 1

lo che vy=0 20 at top of rocks Xx= constant, va K 21 cm Steph using 3rd vy Z T 100 equation of motion for vertical velocity v² u²+zas 0- vj + 2(-9,8) X 0.40 Ny= 104 m/s 18 stepa Find time of flight from ist equation of motion t= 104-o Oo 4 428 s 9-8 step3 / Now, 0-21m Vx= 001428 5² so | Vox = 1.47m/s, voy Ans f. 47 m/s Voy =104 mg

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