Develop a C++ program which will play a simplified version of
the dice game Yahtzee
For simplicity, this version of the game only uses four dice
No prompting of the user for input values is
required
Simply use four variables called A, B, C, D to maintain
dice roll values
No input validation is required as well
From the input you will determine if the player rolled 4 of a kind, 3 of a kind, 2 pair, 1 pair, or nothing
Compare each of the four values against each
other value exactly once. A vs B, A vs C, A vs D, B vs C, B vs D, C
vs D
This means you will have six total comparisons to make
For a given comparison test that both values are equal to one
another
You can determine the result of the roll using the following logic:
Display the result of the roll after you have computed it as described
EXAMPLE: 1 1 3 2 is one pair
EXAMPLE: 1 3 3 3 is 3 of a kind
EXAMPLE: 5 5 5 5 is 4 of a kind
EXAMPLE: 1 3 3 1 is two pair
EXAMPLE: 1 2 3 6 is nothing
THE CODE FOR THE GIVEN QUESTION IS:
In this program, the variables A,B,C,D are stored in an array and are compared with one another using if statement in a for loop.
#include <iostream>
using namespace std;
int main()
{
int A=1,B=1,C=3,D=2;
int count=0;
int Array[]={A,B,C,D};
for(int i=0;i<3;i++)
{
for(int j=i+1;j<4;j++)
{
if(Array[i]==Array[j])
{
count++;
}
}
}
if(count==6)
cout << A<<" "<<B<<" "<<C<<"
"<< D << " is 4 of a kind" << endl;
else if(count==3)
cout << A<<" "<<B<<" "<<C<<"
"<< D<< " is 3 of a kind" << endl;
else if(count==2)
cout << A<<" "<<B<<" "<<C<<"
"<< D << " is two pair" << endl;
else if(count==1)
cout << A<<" "<<B<<" "<<C<<"
"<< D << " is one pair" << endl;
else
cout << A<<" "<<B<<" "<<C<<"
"<< D << " is nothing" << endl;
return 0;
}
The Above code is tested for all the above input values and the outputs are exactly the same.
In the code, the variables are assigned as A=1,B=1,C=3,D=2.
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