Question

In lab, we noted that pressure (which should be the same for both gases) is a product of the strength of the collision times the frequency of collisions. The strength is proportional to mv, and the frequency is proportional to v. If we take the mass of hydrogen to be 4 kg and the speed to be 3 m/s (yes - these numbers are ridiculous for a molecule of gas - but the goal here is to focus on concepts and not get realistic numbers), and if we take the mass of oxygen to be 9kg, what is the speed of the oxygen?

1. speed of oxygen = m/s

2. What is the strength (mv) for the hydrogen? strength of hydrogen collision = kg m/s

3. What is the strength of the oxygen collisions? strength of the oxygen collisions= kg m/s

4. Which statement summarizes how hydrogen (a less massive element) can exert the same pressure as oxygen (a more massive element) at the same temperature, volume, and number of molecules?

Hydrogen collisions with the walls are more frequent but less strong compared to oxygen.

Hydrogen collisions with the walls are equally frequent and equally strong compared to oxygen.

Hydrogen collisions with the walls are less frequent but more strong compared to oxygen.

Answer 1

PAGE NO. 100114 DATE: 1 & speed of oxygon ? mis Preuure = (strengths of collision) ( frequency of collision) (mu) (u) Emv2 As given pressure of both gases are same 4 (3) 2 - 9 v2 - Vo2 = 2 10,= 2mls speed at onggon = 2m15 Ang strength of hydrogen Collision & ; = 4(3) = 12 kg mis 3 strengthy of oxygen collision = m., vom =(9) (2) = 18 kg mis 2 Peptrogen con exchel same presure at same temperature Volume and number of molecule becaure - " Hydrogen Collision with the wall are more frequent but ley strong Compared to oxygon"