Prob. 3 If a 2-kg particle moves along a path given by: r(t) = 5 m...

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Answer 1

Answer #1

given
r(t) = 5 m
theta(t) = 2*t

The motion can be called uniform circular motion

angular velocity, w = d(theta)/dt

= d*(2*t)/dt

= 2 rad/s
The magnitude of net force = m*a

= m*r*w^2

= 2*5*2^2

= 40 N <<<<<<-----------Answer

magnitude of acceleration = r*w^2

= 5*2^2

= 20 m/s^2 <<<<<<-----------Answer

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Answer 2

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