Question

rope block A5 kg block is sliding on a horizontal surface while being pulled by a child using a rope attached to the center of the block. The rope exerts a constant force of 28.33 N at an angle of 0 = 30 degrees above the horizontal on the block. Friction exists between the block and supporting surface (with Mg = 0.23 and Uk = 0.15). What is the horizontal acceleration of the block?

Answer 1

SAF. to 7 m = mass of block isleg F = 2803372 o = 30° Ms = 0.23 7 Mie = 0.15 from Newton's and law mape E. Fy=0 f. BD of bloere => N + F Sino= mg am F Bimo > N = Normal force = mg-f Bino =34.8859 FLOBO fl = limiting lovebion= ME'N = Msing Ffino) =0.23% (5x9.81 – 28-33 87307 = 8:02N te = kine bic Lochion > Men N=0:15 X 34.885 = 5.233 N Ź Fo=ma F1080-fi * Froso - fie =ma =) a = 28-3310130-5•233 -= 3.86 m/s2 acceleration of block =a=3086 m/s2 m a=