The first step in the Ostwald process for producing nitric acid is
4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g).
If the reaction of 0.15kg of ammonia with 0.15kg of oxygen gas yields 87g of nitric oxide, what is the percent yield of this reaction?
Molar mass of NH3,
MM = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass(NH3)= 150.0 g
use:
number of mol of NH3,
n = mass of NH3/molar mass of NH3
=(1.5*10^2 g)/(17.03 g/mol)
= 8.806 mol
Molar mass of O2 = 32 g/mol
mass(O2)= 150.0 g
use:
number of mol of O2,
n = mass of O2/molar mass of O2
=(1.5*10^2 g)/(32 g/mol)
= 4.688 mol
Balanced chemical equation is:
4 NH3 + 5 O2 ---> 4 NO + 6 H2O
4 mol of NH3 reacts with 5 mol of O2
for 8.806 mol of NH3, 11.01 mol of O2 is required
But we have 4.688 mol of O2
so, O2 is limiting reagent
we will use O2 in further calculation
Molar mass of NO,
MM = 1*MM(N) + 1*MM(O)
= 1*14.01 + 1*16.0
= 30.01 g/mol
According to balanced equation
mol of NO formed = (4/5)* moles of O2
= (4/5)*4.688
= 3.75 mol
use:
mass of NO = number of mol * molar mass
= 3.75*30.01
= 1.125*10^2 g
% yield = actual mass*100/theoretical mass
= 87*100/1.125*10^2
= 77.31%
Answer: 77 %
The first step in the Ostwald process for producing nitric acid is 4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g)
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H₂O that can be produced by combining 73.3 g of each reactant? 4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g) mass: _______ g H₂O
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H₂O that can be produced by combining 70.8 g of each reactant? 4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g) mass: _______ g H₂O
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H₂O that can be produced by combining 78.0 g of each reactant? 4NH₃(g)+5O₂(g)⟶4NO(g)+6H₂O(g)
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H₂O that can be produced by combining 61.7 g of each reactant? 4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g) mass: _______ g H₂O
The first step in the Oswald process for producing nitric acid is 4NH+5o2- 4NO + 6H2O if 132g of ammonia reacts with 132g of oxygen A) how many grams of nk itric oxide(No) will be produced B) which compound is limiting reagent C) what is the % yield of this reaction if actual yield of NO is 67.Og?
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H₂O that can be produced by combining 68.6 g of each reactant? 4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g) mass: _______ g H₂O
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H₂O that can be produced by combining 74.3 g of each reactant? 4NH₃(g) +5O₂(g) → 4NO(g) + 6H₂O(g) mass: _______ g H₂O
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H2O that can produced by combining 67.5 g of each reactant? 4NH3(g)+5O2(g)-------- >4NO(g)+6H2O(g)
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H2OH2O that can be produced by combining 86.7 g86.7 g of each reactant? 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(g)
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H, O that can be produced by combining 57.1 g of each reactant? 4 NH3(g) + 502(g) → 4NO(g) + 6H2O(g) mass: - mass: ho