Question

A golf ball is launched with the initial conditions shown in the figure. Determine the radius of curvature of the trajectory

(b) At the apex, determine the speed v of the ball, the total acceleration a of the ball, the normal component of acceleratio

X V = ft/sec a = 32.2 ft/sec2 an ft/sec2 ft/sec2

Determine the radius of curvature of the trajectory and the time rate of change of the speed of the ball just after launch.

(A) answers,

(a) Just after launch, determine the speed v of the ball, the total acceleration a of the ball, the normal component of accel

Answers: V = 264 ft/sec 3 = 32.2 ft/sec2 an 30.624 ft/sec2 at |-9.95 ft/sec2


(a) Determine the radius of curvature of the trajectory and the time rate of change of the speed of the ball just after launc
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Vector diagram at milho V= 180 dan O=180 18 gsins go, 18 velocity of golf ball (u) = 180 mil/hr V = 180 X 5280 3600 V = 264 fCriven Acceleration due to gravity g= 32.244,4 Normal componaut of velocity an=ogcoso an = 32.2 ws 18 an = 30.624 ft/s2 tangeaktan a - acceleration Q 9.95€ + (30-624) R a= 32.2 1/32 V2 Bul an = 8 V2 corvature (89 - an Radily of pa (264) ² 30.624 p=22

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