Question

Main Menu Chapter Menu Chapter: Particle Kinematics Article: Coordinate Systems: 2-D-Normal and Tangential 29 adabe fasu Ball Velocity J ie B9.235 fsec 75, 133 (sec 32.2 ft/sec 116.653 tsec Tme 3 933 sec Positions Repeat Example: A ball is thrown with initial speed Vo = 30° from the horizontal. Determine the radius of curvature p and the time-rate-of-change v of the speed for the positions which are "frozen" during the motion simulation. (The positions are for the times t-0,t-0.8 sec, t=1.6 sec,1- 2.4 sec, and t 103.04 ft/sec at an angle 0= 3.6 sec.) p Slides alichapters 5/5 PExample-pin-circl.. PLecture.pptx-Po.. Adobe Flash Playe..

Answer 1

Here we apply kinematics 2 dimensional motion concept and circular motion concept.

Inistialpeed lo3.04/ec ectap Alony ay 1 Spee VSiegt Cas 2 PezJC Sino gt V 2 singt of cusatuxe We knowy adh OY Y 32.2C103.04) 3

ding (3.48 xl64)(lo3.04)3升- 380-1ft |Y I0304 (S22g 2ni CO8 つけニ 92-88 f Y=218.82ft a - 6sec JQe304)+(222てL-(lo2.04)22)(-6) 83.24t て8924) 3.48 Xlo 247.3 f+ -2.4aec laaot3222.4-(342322.4) 92.88 ftec 3 9= 218-22f+ 3.6 sec Cl03.0 3.2 Clo3n4QY) 110 ftec (3 48 xl0 C10)3 fd 463 19 fd

dud J1 2 VoSine J2d22vsino gt (V-2 2V as psin3ef VD \ = 222fA/ac2 2- 6-1 1a3.04X32-2)- 2(32-2)8 2292-88) 8-93 St/s モ=|-6eC Klo304-2013-322 9-242 t-2.4ec Cla304-2(2-4E222) 2(9288. -8.92 2 C0304)-2(36(32)3(32,2). is t 3.6 e F58.81