Mass of acetic acid = 2.00 g.
Molar mass of acetic acid = 60 g/mol
Moles of acetic acid = mass / molar mass = 2.00 / 60.0 = 0.0333 mol
From the balanced equation,
Moles of NaOH = moles of acetic acid = 0.0333 mol
Molarity of NaOH = 0.258 M
Volume of NaOH = Molles / molairty
V = 0.0333 / 0.258
V = 0.129 L
V = 129 mL
Therefore,
Volume of NaOH solution required = 129 mL
5. How many milliliters of 0.258 M NaOH are required to completely neutralize 2.00 g of...
5. How many milliliters of 0.258 M NaOH are acid HC2H3O2? required to completely neutralize 2.00 g of acetic
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ensune prper 4. What is the function of an indicator in a titration? 5. How many milliliters of 0.258 M NaOH are required to completely neutralize 2.00 g of acetic acid HC2H3O2? 6. What is the volume, in milliliters, of a 0.350 M KOH needed to completely neutralize 15.0 mL of a 0.250 M H2SO4 solution? 2KOH(aq)+H2SO4 (aq) K2SO4 (aq) + 2H,O() 231
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24. How many milliliters of 2.00 M H,SO, will be required to neutralize 45.0 mL of 3.00 N KOH? 25. A careless laboratory assistant set out to determine the concentration of a perchloric acid (HCIO.) solution. He found that 50.00 mL of 1.000 N NaOH neutralized 0.5000 L of the HClO, solution. His calculations were as follows: N (50.00 mL)(1.000 N) 2 = 100.0 N HCIO, 0.5000 L Another laboratory assistant insists that the calculation is incorrect. Why? What is...
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