Question

Data to Graph Experiment: You determine how many grams of solid & gas every 10° increase in temperature. Tem perature of water gas/100ml of water grams of solid/100ml of water gramso 10°C 20°C 30°C 40°C 50 C 60°C 70°C 13 17 27 30 39 43 50 56 0.46 bcm 0.33 Bon 0.24 2나 cnn 0.17 = 13cm 0.09 =9Cvn 80°C 0.033 90°C 0.01 =1cm

Answer 1

a) Independent variables are temperature and mass & dependent variables are grams/100 mL

b) relationship for solid is a direct one because with increasing temperature, the mass of solid or gas per 100 mL of water increases almost linearly. For gas, it is an inverse one since on increasing temperature, mass of gas per 100 mL water decreases.

c) the graphs are as shown

0.5 y 0.6183x + 0.4167 0.45 R 0.9948 0.4 0 9986 0.3 0.25 0.2 0.15 0,05 Temperature temperature

linear for solid and curve for gas

d) plotting a graph of temperature (x-axis) vs mass/100 mL (y-axis)

we get the equation of line as (using any 2 points on the graph and after calculating the slope) :

y = 0.6183x + 0.4167

to calculate the temperature corresponding to dissolution of 38 g/100 mL of water, we use the same equation

y= 38 and x= unknown temperature

38 = 0.6183x + 0.4167

x = 60.8 ⁰C

e) It mentions about 'graph b' which is not mentioned anywhere so I couldnt figure out which one is it.

though, for the solid/100 mL line, the slope = (y-axis) / (x-axis) = 0.6183

and for gas, slope depends on what type of graph we consider; for a log curve slope = -0.21

units = (grams/100 mL)/ ⁰C = g ml^-1 ( ⁰C^-1)

These units mean that this value corresponds to the amount of a substance in grams that can dissolve per 100 mL of water per degree celcius rise in temperature.

Quest 1 :

I did not have a graph paper in hand. Also since further, regression using a calculator is required, i used excel for everything.

for plotting manually on a graph paper, u can use x- axis for diameter (D) with a scale of 1 cm of x-axis= 0.02 units of D and y-axis for mass (M) with a scale of 1 cm of y-axis = 5 units of M

The graph will look like this:

:52 10.0321 20.0375 0.044 40:0501 0.0525 60.066 0.075 2 Chart Title 6.6 8.56 9.5 у-3384 6x4 62224x-0.1929 35 19.3 80083123.7 36 90.1025 10 12 13 14 15 16 17 18 19 20 15 10 0.05 0.08 0.1 012 002 0.04 Sheet1

the resulting plot indicates a power relationship between the variables

the regression equation and constant is:

y = 3384.6x² + 6.2224x - 0.1929
R² = 1

here, x= D and y= M

therefore in terms of variables-

M = 3384.6D² + 6.2224D - 0.1929