Question

(Count the occurrences of each keyword) Write a python program that reads in a Python source code file and counts the occurrence of each keyword in the file. Your program should prompt the user to enter the Python source code filename.

Answer 1

#!/usr/bin/env python3
"""Count the occurrences of each keyword
Write a program that reads in a Python source code file and counts the
occurrence of each keyword in the file.
Your program should prompt the user to enter the Python source code
filename.
"""
import os
from counter import Counter

keywords = """
and       del       from      not       while
as        elif      global    or        with
assert    else      if        pass      yield
break     except    import    print
class     exec      in        raise
continue finally   is        return
def       for       lambda    try
"""

if __name__ == "__main__":
    filename = input('Enter filename: ')
    keywords = keywords.split()
    if os.path.isfile(filename):
        with open(filename, 'r') as f:
            data = f.read().split()
            C = Counter(data, keywords)
            matched = C.collection
            f.closed
            for item in matched.items():
                print('Keyword "{}" occur {} times'.format(
                    item[0], item[1]
                ))
    else:
        print('File "{}" does not exist!'.format(filename))
      
      
Counter.py

#!/usr/bin/env python3

class Counter:

    def __init__(self, data, pattern=None):
        self.data = tuple(data)
        self.pattern = [str(i) for i in pattern] if pattern else None
        self.collection = dict()
        if self.pattern:
            self.matching()
        else:
            self.count()

    def count(self):
        # if data is string or list
        for item in self.data:
            item = str(item) # just for consistency
            if item in self.collection:
                self.collection[item] += 1
            else:
                self.collection[item] = 1

    def matching(self):
        # if data is string or list
        for item in self.data:
            item = str(item) # just for consistency
            if item in self.pattern:
                if item in self.collection:
                    self.collection[item] += 1
                else:
                    self.collection[item] = 1

    def duplicates(self):
        c = self.collection
        return {i:c[i] for i in c if c[i] > 1}

    def uniques(self):
        c = self.collection
        return {i:c[i] for i in c if c[i] == 1}