A 0.46-mm-diameter hole is illuminated by light of wavelength 540 nm .
What is the width (in mm) of the central maximum on a screen 2.0 m behind the slit?
Here,
L= 2 m
Lamda= 540 nm = 540 *10^-9 m
Then,
A 0.46-mm-diameter hole is illuminated by light of wavelength 540 nm . What is the width...
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