A 0.42-mm-wide slit is illuminated by light of wavelength 540 nm .
What is the width (in mm) of the central maximum on a screen 1.6 m behind the slit?
Express your answer using two significant figures.
w = ( )mm
width (in mm) of the central maximum
= 2 lambda * D / d
= (2 * 540 * 10-9 * 1.6) / (0.42 * 10-3)
= 4.11 * 10-3 m
= 4.11 mm
A 0.42-mm-wide slit is illuminated by light of wavelength 540 nm . What is the width...
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