33.
a)
Let p1 and p2 be the percentage of near negative equity
mortgages in Arizona and Nevada respectively.
Null hypothesis H0: p1 - p2 = 0
Alternative hypothesis Ha: p1 - p2 0
For Arizona, x1 (success) = 62
failures, n1 - x1 = 1369 - 62 = 1301
For Nevada, x2 (success) = 22
failures, n2 - x2 = 604 - 22 = 582
Since each sample includes at least 10 successes and 10 failures, we can use two-proportion z-test.
For this analysis, the significance level is 0.1 (90% confidence interval).
Pooled proportion, p = (x1 + x2) / (n1 + n2)
= (62 + 22) / (1369 + 604) = 0.04257476
Standard error of pooled proportion, SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2) ] }
SE = sqrt{ 0.04257476 * ( 1 - 0.04257476 ) * [ (1/1369) + (1/604) ] } = 0.009862156
p1 = x1 / n1 = 62 / 1369 = 0.04528853
p2 = x2 / n2 = 22 / 604 = 0.03642384
Test statistic, Z = (p1 - p2) / SE = (0.04528853 - 0.03642384) / 0.009862156 = 0.8989
For two tail test, p-value = 2 * P(z > 0.8989) = 0.3687
Since, p-value is greater than 0.1 significance level, we fail to reject null hypothesis H0 and conclude that there is no strong evidence that percentage of near negative equity mortgages is different in two states.
b)
z value for 90% confidence interval is 1.28
Margin of error = z * SE = 1.28 * 0.009862156 = 0.0126
Point estimate of the percentage difference = p1 - p2 = 0.04528853 - 0.03642384 = 0.0089
90% confidence interval of the difference in percentage of near negative equity mortgages in two states is,
(0.0089 - 0.0126, 0.0089 + 0.0126)
(-0.0037, 0.0215)
34.
a)
Let p1 and p2 be the percentage of construction workers who are
illegal short-term migrants in two regions respectively.
Null hypothesis H0: p1 - p2 = 0
Alternative hypothesis Ha: p1 - p2 0
For NorthEast, x1 (success) = 66
failures, n1 - x1 = 958 - 66 = 892
For MidWest, x2 (success) = 42
failures, n2 - x2 = 1070 - 42 = 1028
Since each sample includes at least 10 successes and 10 failures, we can use two-proportion z-test.
For this analysis, the significance level is 0.1 (90% confidence interval).
Pooled proportion, p = (x1 + x2) / (n1 + n2)
= (66 + 42) / (958 + 1070) = 0.05325444
Standard error of pooled proportion, SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2) ] }
SE = sqrt{ 0.05325444 * ( 1 - 0.05325444 ) * [ (1/958) + (1/1070) ] } = 0.009987433
p1 = x1 / n1 = 66 / 958 = 0.06889353
p2 = x2 / n2 = 42 / 1070 = 0.03925234
Test statistic, Z = (p1 - p2) / SE = (0.06889353 - 0.03925234) / 0.009987433 = 2.9678
For two tail test, p-value = 2 * P(z > 2.9678) = 0.003
Since, p-value is less than 0.1 significance level, we reject null hypothesis H0 and conclude that there is significantly strong evidence that percentage of construction workers who are illegal short-term migrants in two regions are different.
b)
z value for 90% confidence interval is 1.28
Margin of error = z * SE = 1.28 * 0.009987433 = 0.0128
Point estimate of the percentage difference = p1 - p2 = 0.06889353 - 0.03925234 = 0.0296
90% confidence interval of the difference in percentage of near negative equity mortgages in two states is,
(0.0296 - 0.0128, 0.0296 + 0.0128)
(0.0168, 0.0424)
I 33. Under water. In early 2012, the proportion of mortgages that were “under water"-a negative...