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Question 2 1 pts Suppose the lifetime (in months) of certain type of battery is a random variable y with pdf =x2. In a random

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Answer #1

P(a battery work for more than 6 months)=6f(x) dx=6 8/x3 dx =-4/x2 |\infty6 =4/36=1/9

hence from binomial distribution at least 2 of 4 work more than 6 months)=0.0636 ~ 0.06

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