Question

This question has multiple parts. Work all the parts to get the most points. Use the References to acces important valees if neded for this qeention The pH of a solution is defined by the equation pHlogH] H]-hydrogen ion concentration Use the rules for logarithms and exponents to solve for H Where in terms of pH Submit Relry Entine Grcsp 40

Answer 1

Given, p^H = -log [H^+] I) multiply with -1 on both sides -p^H = log [H^+] II) apply log^-1 on both sides log^-1 [-p^H] = [H^+] [Because log^-1, log = 1] log^-1(x) = 10^x - Therefore 10^-p^H = [H^+] Therefore [H^+] = 10^-p^H Given, [H^+] = 10^-p^H I) Apply log on both sides, log [H^+] = -p^H [Because log^-1 middot log = 1, & log^-1(x) = 10^x) II) multiply with -1 on both sides -log [H^+] = p^H - Therefore p^H = -log[H^+]