Question

Two capacitors are connected to each other and the battery is removed. The voltage across each capacitor is 5.5 volts. V = V1 = V2 = 5.5 V. The capacitance of C1 = 1.0 x 10 ^-6 F and the capacitance of C2= 2.0 x 10 ^-6 F. What is the charge on each capacitor? If the gap between the plates of C1 if filled with paraffin (dielectric constant K=2.2) what is the new charge on each capacitor and what is the new voltage across each capacitor? [The total charge is conserved and the voltage across the first capacitor is still equal to that across the second capacitor.] Calculate the total stored potential energy of the charged capacitors before and after the paraffin was added. Was there a loss or gain of potential energy when the dielectric was inserted? What % of the original potential energy was gained or lost?

Answer 1

トーニー1.Ο.Xlo-SF -- 2 4 15 6 5 K.