The answer is D) 4.9×10^2g
Osmotic pressure , = MRT
Where, M = molarity of solute
R = gas constant ,0.0821(Lit atm / mol K)
T = Temperature in K , 298K
Therefore,
14 atm = M × 0.0821(Lit atm / mol K ) × 298K
M = 14 atm /( 0.0821(Lit atm / mol K) × 298K )
= 0.5722M
Therefore, Molarity of sucrose = 0.5722M = 0.5722 mol /Lit
For 2.5Lit sucrose solution no of mole of sucrose need= 0.5722(mol/Lit)× 2.5Lit = 1.4305mol
Molar mass of Sucrose = 342.3g/mol
Mass of Sucrose = No of mole × molar mass
= 1.4305 × 342.3g = 489.66g = 4.9×10^2g
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