Question

REFER TO THE FIGURE BELOW (Fig. 14.3 in the textbook) TO ANSWER QUESTIONS 5-7. B Vapor 150 - 130 110- Liquid TA Temperature 70- 50- A 100%-80% 0% 20% 60% -40% 40% 20% 0% -60% -80% — 100% B 5. This graph represents the behavior of a mixture of liquids A and B as it is heated, according to its initial composition as shown on the x-axis. The boiling point of pure A is ta, and the boiling point of pure B is tg. But a mixture of composition W (approximately 30% A and 70% B) will boil at temperature t. What is the approximate composition of the vapor in equilibrium with this boiling liquid? ANSWER: 6. What is the approximate boiling temperature of a mixture consisting of 60% A and 40% B? ANSWER:

Answer 1

Q5) Vapor Composition - 70% A and 30%B

Q6) App. boiling point = 110 units (units not mentioned in question)

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Explanation :

Q5)

To get vapor composition

1. From W, go up till you reach curved line - Liquid (Point X)
2. From X, go left till you reach curved line - Vapor (Point Y)
3. From Y, go down till you reach x-axis (Point Z)
4. Point Z gives the vapor concentration at boiling point for the initial composition W.

Here, Z = 70% A and 30% B, which is required vapor concentration at boiling point

Q6)

To get Boiling Point

1. From P, go up till you reach curved line - Liquid (Point Q)
2. From Q, go left till you reach y-axis (Point R)
3. Point R give the boiling point.

B Vapor 150 130 R 110 - Q Liquid - IA - Temperature - - 50 1 - (z w A 100%-80% 60% - 40% 20% 0% 0% -20% -40% -60% -80% - 100% B

From graph, approximate boiling point = 110 units

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