In order to formulate the problem as a transportation model, we need to create the parameter table as below | |||||
Rows of the parameter table show supply period and columns indicate demand period | |||||
Regular cost of production in a supply period to fulfil the demand of same period is as given in the problem. For example regular production cost in period 1 to fulfil the demand of period 1 is $ 875 and overtime cost in the same supply and demand period is $ 1310. Subcontract cost is $ 1600 | |||||
Regular time Cost of fulfilling demand of n period later than the current period increases by n times the carrying cost. For example, cost of fulfilling demand of period 4 (3 period later) from overtime time supply of period 1 = 1310+3*100 = 1610 | |||||
While calculating net demand, opening inventory is subtracted from first month demand and required closing inventory is added to the last month demand. | |||||
Resulting parameter table is as follows |
Parameter Table | |||||
Supply | Mth 1 | Mth 2 | Mth 3 | Mth 4 | Supply |
Mth 1 Regular | 875 | 975 | 1,075 | 1,175 | 225 |
Mth 1 Overtime | 1,310 | 1,410 | 1,510 | 1,610 | 15 |
Mth 1 Subcontract | 1,600 | 1,700 | 1,800 | 1,900 | 14 |
Mth 2 Regular | 875 | 975 | 1,075 | 275 | |
Mth 2 Overtime | 1,310 | 1,410 | 1,510 | 28 | |
Mth 2 Subcontract | 1,600 | 1,700 | 1,800 | 15 | |
Mth 3 Regular | 875 | 975 | 300 | ||
Mth 3 Overtime | 1,310 | 1,410 | 26 | ||
Mth 3 Subcontract | 1,600 | 1,700 | 13 | ||
Mth 4 Regular | 875 | 300 | |||
Mth 4 Overtime | 1,310 | 28 | |||
Mth 4 Subcontract | 1,600 | 15 | |||
Net Demand | 240 | 318 | 331 | 305 |
Formulas:
M12 =SUM(I12:L12) copy to M12:M23
I24 =SUM(I12:I23) copy to I24:L24
M9 =SUMPRODUCT(B12:E23,I12:L23)
The optimal cost = $ 1,091,440
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