Question

Two long, parallel conductors separated by 11.0 cm carry currents in the same direction. The first wire carries current 11 = 3.00 A, and the second carries 12 = 8.00 A. (Assume the conductors lie in the plane of the page.) (a) What is the magnitude and direction of the magnetic field created by I1 and acting on I2 (b) What is the force per unit length exerted on 12 by 11 (c) What is the magnitude and direction of the magnetic field created by I2 at the location of I1? (d) What is the force per length exerted by I2 on 11? T Direction N/m Direction T Direction N/m Direction

Answer 1

Distance b/w the conductors v = 0.11 current carried by the first wire, I1 = 3A current carried by the second wire I_2 = 8A B1 = (mu_0/2 mu)(I1/r_0) = 2 times 10^-7 times (3/0.11) = 5.45 times 10^-6 T magnitude of B1 = 5.45 times 10^-6 T Direction: +ve z- direction F_2 = B-1 times 12 times L = 5.45 times 10^-6 times 8 times 1 = 4.36 times 10^-5 N magnitude of B1 = 4.36 times 10^-5 N direction: -ve y direction B_2 = (mu_0/2 mu)(I2/r_0) = 2 times 10^-7 times (8/0.11) = 1.45 times 10^-5 T Magnitude of B_2 = 1.45 times 10^-5 T Direction: -ve z - direction F1 = B2 times I1 times L = 1.45 times 10^-5 times 3 times 1 = 4.36 times 10^-5 N Magnitude of B1 = 4.36 times 10^-5 N Direction: +ve y direction