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Test the hypothesis, using (a) the classical approach and then (b) the P-value approach. Be sure to verify the requirements o

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Answer #1

Sample proportion \hat{p} = 75/100 = 0.75

Test statistics

z = \hat{p} - p / sqrt(p(1-p) / n)

= 0.75 - 0.6 / sqrt( 0.6 * 0.4 / 100)

= 3.06

a)

Critical value at 0.05 level is 1.645

Reject the null hypothesis.because test statistics is greater than critical value.

b)

p-value = P(Z > z)

= P( Z > 3.06)

= 0.0011

Reject the null hypothesis because p-value is less than \alpha

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