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Problem 7.036 A long, cylindrical, electrical heating element of diameter D 10 mm, thermal conductivity k240 W/m- K, density

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Given Dtomm 00 m LE 2900 (kgl) k 240 wimk Spe 900 (31k k) 27°c-300k VE20 ms given to evaluate Frem air paopaty teble ai paopeशक्र Nu 40.68= 0.0393 ha 151.736 (Wimk) Ergy balance tar steedy Stati h7PT-T Pesect यहट TTe t Peleat TiDh T: 300 t lo00 Tlx 0अक5 . Using lucaped capacidance equatiaa T-Tet b11-cpcat) a whac a 4x1S1.736 O.01x 2t00x 900 0.02491 (S) Pelact (000 a x 0.01-0.02491 xt = -3.0455 t 3.04 55 0.02497 t (21.96 (seconds) t = 12196 (s) Time t-121.96 (S) qied is 6- Stक_ T+ T 17 2 509-79+Using general heat transfer formula and energy balance to get the result.

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