The position vector for a proton is initially r = 8.0i -6.0j + 2.0k, and then...

Question

Question

The position vector for a proton is initially

r = 8.0i -6.0j + 2.0k, and then later is

r = -3.0i + 6.0j + 2.0k, all in meters. What is the proton's displacement vector i-component?

j-component?

k-component?

To what plane is it parallel ('xy', 'xz', 'yz')?

Answer 1

Answer #1

Fas hox Men u 3844.iv L compenent- dishlac emant wdus Conteino

Answer 2

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