6. A 40.0-W lightbulb is connected to a 220.0-V source.
(a) What is the current through the bulb?
A
(b) What is the internal resistance of the bulb?
?
If you could provide a step by step solution, that would be great.
Ans: Given Power consumed by the bulb of resistance R is P= 40 W
Voltage applied is V= 220 V
a) Current through the bulb is I= P/V = 40/220 = 0.1818 A = 0.182 A= 182 mA
b) Internal resistance of the bulb is R= V/I = 220/ 0.182 = 1210 ohms
6. A 40.0-W lightbulb is connected to a 220.0-V source. (a) What is the current through...
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