Question

A) Determine the resistance of a 75-W lightbulb connected to its proper source voltage of 110 V. 

B) Determine the current through a 75-W lightbulb connected to its proper source voltage of 110 V.

C) Determine the resistance of a 250-W lightbulb connected to its proper source voltage of 110 V.

D) Determine the current through a 250-W lightbulb connected to its proper source voltage of 110 V.

No referring, please.

Answer 1

b) I = 75/110 = 0.682 amps

a) R = 110/0.682 = 161 ohms

d) I=250/110 = 2.27 amps

c) R = 110/2.27 = 48.45 ohms

Answer 2

v2 1102 P 75 A) Resistance of the bulb is given by,R- 161.332 B) Current through the bulb is, I = -0.68A VR V161.33 v2 110* P 250 C) Resistance of the bulb, R 484Ω P 1250 D) Current through the bulb, I-S

Answer 3

A) P= V^2/R so, R= V^2/P , therefore, R= 110*110/75 = 161.33 ohm

B) P= VI so I =P/V , therefore , I =75/110 = .68 Ampere

C) P= V^2/R so, R= V^2/P , therefore, R= 110*110/250 = 48.4 ohm

B) P= VI so I =P/V , therefore , I =250/110 = 2.272 Ampere