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student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a...

student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in calorimeter is determined to be 20.9 °C. To this is added 50.0 mL of water that was originally a temperature of 54.6 °C. A careful plot of the recorded temperature established T0 as 31.1 °C. What is the calorimeter constant (J/°C)?

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Answer #1

ho wlex wates4 18tJ = 50g x 4-184 J/ge x (54.6c-31.1%) 4916. ned y the told wake, M10 2133.84 J2T8 36 J Rime Mea Capwi

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