Question

1. A table tennis ball of mass 9g carries a charge of +7UC. What a magnitude and direction of the electric field required for the ball to be suspended above the ground? magnitude but opposite 2. An electric dipole consists of two charges with equal magnitude buto signs, separated by a small distance d. Charges qi(9) and 92 located on the y-axis as shown in the figure, separated by a distance the field at point A located at (0,2). a=d/2 Dipole * dl centre a=d/2 intral axes

Answer 1

consider a table tenis ball of mass Suspended as bellon qq which in To balance for the ball abone do stround, we need a force (electrostatie) just opperige direction of the gravitational force (down-ewond) Therefore from sue fig. Fale = Farar. a o q El= faran & mg los mg = Farov. a les mo whene tele - for a Elofon static Eloo for static for force =9E - charge & Eletric field the magnitude of eletric field Therefore 98 x 10 mis2 7 4с 09x103 kg x 10 mis? 7410- 3c 9x10 A leg. m/src

2 dipole at a we know the electric field due to a point f ontoro [38.7) or -p] --- Ź 1612) DIS where ř 5 in unit veedor dipale moment Here î= P = qd = qd (-a) Tas dipole direction it' charge to w' charge ] Ayaz at a distance & from Non uning the equation contre we will have Estate 23 [ > Cadês ējë – (1982)] FR629 [-3.+] - -290 ê CRG 23 CAGO 23