A satellite in a circular orbit 500 miles above the surface of
the Earth. What is the period of the orbit? You may use the
following constants:
Radius of the Earth: 4000 miles
Gravitational Constant: 66710?11m3(kgs2)
Mass of earth: 5981024kg
Number of Meters in a mile: 1609
Period= ? seconds
A satellite in a circular orbit 500 miles above the surface of the Earth. What is...
Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit has an orbital period of exactly one day. Assume a spherical Earth, and use the following constants (taken from Vallado, David A., Fundamentals of Astrodynamics and Applications, 2nd ed. 2001) Gravitational constant: G 6.673 x 10-20 km Radius of the Earth: Re = 6378.137 km 1024 kg Mass of the Earth: Me = 5.9733328 x Round your final answer to four...
Find the height H of a geosynchronous satellite above the surface of the earth. You may well want to find the radius of the orbit R first. You may use the following constants: The universal gravitational constant G is 6.67×10−11Nm2/kg2. The mass of the earth is 5.98×1024kg. The mass of the satellite is 2.10×102kg. The radius of the earth is 6.38×106m. Give the height of the orbit above the surface in km to three significant digits.
A 544-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m/s (b) Find the period of its revolution. (c) Find the gravitational force acting on it A satellite of Mars, called Phobos, has an orbital radius of 9.4 x 106 m and a period of 2.8 104 s. Assuming the orbit is circular, determine the mass of Mars. x 10 s. Assuming kg
Consider a 435 satellite in a circular orbit at a distance of 3.19X10^4 above the Earth’s surface. What is the minimum amount of work W the satellite’s thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.6X10^4 above the Earth’s surface. The radius of the Earth and the mass of the Earth are RE=6.37X10^3 and 5.97X10^24 respectively. The gravitational constant is G = 6.67X10^-11 Assume the change in mass of the satellite is...
Calculate the speed required to maintain a satellite in an orbit 500 miles above the surface of the earth?
A satellite of Earth is moving in a circular orbit with Earth at its center, at a constant speed of 2.00 km/s. a.) How high is the satellite above the surface of the Earth? b.) How long does it take for the satellite to complete one revolution? Helpful info (but not all of it is relevant!): universal gravitational constant G is = 6.674 x 10^-11 m^3/kg s^2 (units may also be expressed as N m^2/kg^2) Mass of Sun = 1.989...
Required information A spy satellite is in circular orbit around Earth. It makes one revolution in 8.30 h. Mass of Earth is 5.974 1044 kg. radius of x Earth is 6371 km and Gravitational constant G is 6.674 10-11 N-m2/kg x How high above Earth's surface is the satellite? km
10-3. A 639-kg satellite is in a circular orbit about Earth at a height h = 1.16 x 10^7 m above the Earth’s surface. Find (a) the gravitational force (N) acting on the satellite, (b) the satellite’s speed (m/s) (magnitude of its velocity, not its angular velocity), and (c) the period (h) of its revolution. Caution: The radius of the satellite’s orbit is not just its height above the Earth’s surface. It also includes the radius of the Earth. The...
A 534-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m/s (b) Find the period of its revolution. h (c) Find the gravitational force acting on it. N
A 607-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m/s (b) Find the period of its revolution. h (c) Find the gravitational force acting on it. N