Question

How mandmoles NO tan poduad from N.O ALOms Df NO and o t On acordiny to te equation 2 NO +0 NO2 2 6rven the foloung atuan 2 02 N,25moles moles s o n Tor th Maotbn 24 301-3220s, b.ss Cl actS compute with r Pke many grams sA 7ely w cu (4) 1S.o ams o+ CD ond .Sn Oau eombeneol aecoreengo he ooing sauatw cot Oz2 C0 5 IS.0of Ch at tombrned witk46.0 HD molar mass .02) a00rcdai to the uaction 3u48AN (ND NO+ 40 Gohich eautont ts matiny ,and kous manyams of Heo ae pladcac Hna ortain arpou mant La otNHyNO3 Imolor mon 80.00) z488 was pucturd fuom 292 teNos molar ma a acting wt on ex Rs 5 dNHs and uz0 0eordanc, to te atio Te (No,),+ 3 NH54H Te lo4),3 NAy ND.hat Yheoutcal yeld ond arcont ld ot is se ct NHy ND3

Answer 1

Balance Reactiona Solution; Given thout:- 2NO+O2 + 2NO2 mass of no=14.0g molar mass of No =30g/mol mass of O2 = 4.00 molar mass of O2 = 32g/mol mol = Mass molar mass Somoles of NO = 14.00 -0.46 mot 30.g/mol moles of 02= 4.000 ) 0.125 mol 32g/mol Here moles of No is more compare to moles of oz. so moles of Og Firstly Consumeel on reaction complections so limiting Reagent is Ozo According to following Reaction 1 mole O2 Produced a mou - 0.125 mole O2 Produced ax0 125 mole no mole of NO2 = 0.250 moles 1 2 mol No2 So. es - Ans Note: Ist image Not cleaire. Provide clear image