06 Question 1 point) The vaporization of 1 mole of liquid water (the system) at 100.9℃...
06. Question (2 points) The vaporization of 1 mole of liquid water (the system) at 100.9°C, 1.00 atm, is endothermic. H,0(1) +40.7kJ → H2O(g) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62L. respectively. Part 1 (1 point) Il See Periodic Table See Calculate the work done on or by the system when 3.65 mol of liquid H2O vaporizes. Part 2 (1 point)...
The vaporization of 1 mole of liquid water (the system) at 100.9°C, 1.00 atm, is endothermic. HL,0(1) + 40,7kJ + HO( g) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62 L. respectively Part 1 (2.5 points) Calculate the work done on or by the system when 2.05 mol of liquid H2O vaporizes. Part 2 (2.5 points) Calculate the water's change in internal...
The vaporization of 1 mole of liquid water (the system) at 100.9°C, 1.00 atm, is endothermic. H2O(l)+40.7kj -------> H2O(g) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62 L, respectively. Part 1 Calculate the work done on or by the system when 1.25 mol of liquid H2O vaporizes. Part 2 Calculate the water's change in internal energy
Please just answer Part 2 The vaporization of 1 mole of liquid water (the system) at 100.9°C, 100 atm, s endothermic. H0HOg) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62 L, respectively 5th attempt d See Periodic Table See Hint (0.5 point) Part 1 Calculate the work done on or by the system when 1.85 mol of liquid H20 vaporizes. 5736.23319:J (0.5...
I only have 1 attempt left, help please 5 Question point) a See page 376 The vaporization of 1 mole of liquid water (the system) at 100.9°C, 1.00 atm,is endothermic H20 (1) + 40.7kJ → H2O(g) Assume at exactly 100.0°C and 1.00 atm total pressure, 1,00 mole of liquid water and 1.00 mole of water vapor occupy 18.80mL and 30.62L respectively. , 5th attempt Part 1 (0.5 point) ani See Periodic Table See Hint Calculate the work done on or...
The Standard enthalpy of vaporization of water at 100.0 oC is 40.66 KJ*mol-1. The Cp,m values for the liquid and the vapor water are, respectively, 75.3 and 33.58 J*K-1*mol-1. Assume that the heat capacities are independent of temperature, and that the vapor behaves as an ideal gas. a) Calculate sys in taking one mole of liquid water at 25.0 oC and 1.00 atm to gaseous water at 95.0 oC and 0.500 atm. b) Assume that the temperature and pressure of...
Please answer clearly & correctly. Selected properties of water Heat of fusion at the normal melting point: The heat of vaporization at the normal boiling point: Liquid water: 333.55 J/g 2257 J/g Cp = 1.00 cal/(g. K) = 4.184 J/(g. K) or 75.33 J/(mole. K) ρ= 1 .000 g/cm3 Cp = 2.05 J/(g. K) or 38, l J/(mole K) ρ=0.917 g/cm3 Water ice at 0°C and 1 atm Heat capacity of water vapor, H20(g) Cvm 28.03 J/(mol-K).
Consider the vaporization of liquid water to steam at a pressure of 1 atm. Part A Is this process endothermic or exothermic? Is this process endothermic or exothermic? endothermic exothermic SubmitMy AnswersGive Up Part B In what temperature range is it a spontaneous process? In what temperature range is it a spontaneous process? below 100 ?C above 100 ?C below 0 ?C above 0 ?C at no temperature SubmitMy AnswersGive Up Part C In what temperature range is it a...
theres 2 parts to the question. only answer it if u can answer both part 1 and 2 See page 295 A common anesthesia gas is Halothane, with the formula C2HCIBrF3 and the structure is shown in the figure. Liquid Halothane has a density of 1.87 g/mL, and boils at 50.2°C and 1.00 atm. Part 1 (1 point) See Periodic Table If Halothane behaved as an ideal gas, what volume would 10.0 mL of Halothane occupy at 60°C and 1.00...
06 Question (1 point) See page 801 Oxygen Supply in Submarines Nuclear submarines can stay under water nearly indefinitely because they can produce their own oxygen by the electrolysis of water. 1st attempt diui See Periodic Table See Hint Feedback produced in 3.50 hr in an electrolytic cell operating How many liters of O2 at 298 Kand 1.00 bar are at a current of 0.0400 A? 0,00455 L 06 Question (1 point) See page 801 Oxygen Supply in Submarines Nuclear...