Question

Gas Forming Reactions Uu04 Sample Problem 4.13 net om same Practice Problem 4.9 Writing lonie Equations for Acid-Base Reactions Write balanced molecular, total ionic, and net ionic equations for the following acid-base reactions and identify the spectator ions (a) Br (a) hydriodic acid (aq) + calcium hydroxide (aq) - (b) barium hydroxide (aq) + sulfuric acid (aq) + Ba (OH)2 (aq) + H2SO4 (99) ► bos (aq) + H Sov- BaSO4 (5)+ 2 H2O (L) molecular equation + OH KE K+ CH3COO(aq) + H2 (c) Acetic acid (aq) + potassium hydroxide . CH 3 COOH (aq) + KOH (19) -> CH3COOK (aq)+ H2O (L) molecular TONIC - CH3COOH (aq) + 1 (aq) +014 (aq) → CH3C00+ H+ net ionic: CH3COOH(aq) + OH-(99)-> CH3C00 la (d) Hydrofluoric acid (aq) + barium hydroxide (aq) → (e) Ammonium carbonate (aq) + sulfuric acid (aq) - hotellt fire acid (aal (1) Potassium sulfite (aq) + hydriodic acid (aq) -

Answer 1

(a) The molecular equation is 2 HI (aq) + Ca(OH)2 (aq) --------> Calz (aq) + 2 H20 (1) Totalionicequation is 2 H+ (aq) +2 (aq) + Ca+2 (aq) + 2 OH(aq)--------> Ca+2 (aq) +2 (aq) + 2 H2O (1) Net ionic equation is (discard the counter ions) 2 H+ (aq) + 2 OH-(aq)--------> 2 H2O (1) H+ (aq) + OH-(aq)--------> H2O (1) (b) The molecular equation is Ba(OH)2 (aq) + H2SO4 (aq) -------> BaSO4 (s) + 2 H20 (1) Total ionicequation is Ba+2 (aq) + 2 OH- (aq) + 2 H+ (aq) + SO4-2 (aq)--------> BaSO4 (s) + 2 H20 (1) Net ionic equation is (discard the counter ions) Ba+2 (aq) + 2 OH- (aq) + 2 H+ (aq) +504-2 (aq)--------> BaSO4 (s) + 2 H20 (1)

(c) CH3COOH is a weak acid. It does not dissociate completely. Molecular equation is CH3COOH (aq) + KOH (aq) ---------> H20 (1) + CH3COOK (aq) Totalionic equation is CH3COOH (aq) + K+ (aq) + OH- (aq) -------> H20 (1) + K+ (aq) + C2H302 - (aq) Net ionic equation is (discard the spectator (counter) ions) CH3COOH (aq) + OH- (aq) -------> H20 (1) + C2H302 - (aq) (d) HF is a weak acid. It does not dissociate completely. Molecular equation is 2 HF (aq) + Ba(OH)2 (aq) ---------> 2 H20 (1) + BaF2 (aq) Totalionicequation is 2 HF (aq) + Ba+2 (aq) + 2 OH- (aq) -------> H2O (1) + Ba+2 (aq) + 2 F- (aq) Net ionic equation is (discard the spectator (counter) ions) 2 HF (aq) + 2 OH- (aq) -------> H20 (1) + 2 F- (aq)

(e) The molecular equation is H2SO4 (aq) + (NH4)2CO3 (s) --------> (NH4)2SO4 (aq) + CO2 (g) + H2O (1) Totalionic equation is 2 H+ (aq) + S04-2 (aq) + 2 NH4+ (aq) + CO3-2 (aq) --------> 2 NH4+ (aq) + S04-2 (aq) + CO2 (g) + H20 (1) Net ionic equation is (discard the counter ions) 2 H+ (aq) + CO3-2 () --------> CO2 (g) + H20 (1) (f) The molecular equation is 2 HI (aq) + K S03 (aq) --------> 2 Kl (aq) + S02 (g) + H2O (1) Totalionicequation is 2 H+ (aq) + 2 (aq) + 2 K+ (aq) + S03-2 (aq) --------> 2 K+ (aq) + 2 + (aq) + SO2 (g) + H20 (1) Net ionic equation is (discard the counter ions) 2 H+ (aq) + S03-2 (s) --------> S02 (8) + H20 (1)