Question

One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates "artificial gravity" at the outside rim of the station.

Part A

If the diameter of the space station is 900 m , how many revolutions per minute are needed for the "artificial gravity" acceleration to be 9.80m/s2?

Part B

If the space station is a waiting area for travelers going to Mars, it might be desirable to simulate the acceleration due to gravity on the Martian surface (3.70m/s2). How many revolutions per minute are needed in this case?

Answer 1

Acceleration of the space station is 9.80 m/s2 Radius of the space station is, 2 900 m 2 450 m The radial acceleration is 9.80 m/s2 450 m - (0.1475 rad's , )( ) e60 s 1 mitn simplify this for ω as follows: a) 1.1 4 rev/ mln

Acceleration of the space station is a Radius of the space station is. 3.70 m/s2 900 m 450 m The radial acceleration is, 3.70 m/s2 450 m 1 rev\ 60 s -(0.091 rad/s min Simplify this for ω as follows ω = 0.866 rev/min