A monolayer containing 3.15×10^-6 g of oleic acid has an area of 20.0 cm^2. The density...
A monolayer containing 3.15×10^-6 g of oleic acid has an area of 20.0 cm^2. The density of oleic acid is 0.895 g / mL. What is the thickness of the monolayer (the length of an oleic acid molecule)?
Homework Answers
mass = volume * density
3.15*10-6 = volume *0.895
volume = 3.15*10-6/0.895 = 3.52*10-6 ml = 3.52*10-6 cm3
volume = area * thickness
3.52*10-6 = 20*thickness
thickness = 3.52*10-6/20 = 1.76*10-7 cm >>>> answer
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