Question

do you know what i did wrong on this

PART I: Calibration of a Dropper Pipet Trial 1 58 Trial 2.62 1 Number of drops in 1-ml Trial 603 el 2. Average value PART II: Number of Molecules in the Monolayer 2.45cm 4.ssim GO 1 Diameter of the monolayer, cm 2. Number of drops to form monolayer 5+2= 3. Area of the monolayer, cm? 4. Concentration of the stearic acid, g/mL 5. Volume of the stearic acid in the monolayer, ml 3.5cm I drop 9. Loom² 0.001soalmL 1. OmLx 1 +60=0.02mL n=0.02 X 0.848alme=0.02 9.6+(2.1x10-1992) 4.6x1019 1. OXO 9. 666m²/7.0x10-5=1.3x10 100%. 6. Mass of stearic acid in the monolayer, 7. Number of molecules in monolayer 8. Moles of stearic acid in monolayer 9. Avogadro's Number 100 10. % error Puestions List three sources of error and tell how each one affected the calculated value. Explain.

Answer 1

ANSWER:

• Diameter of monolayer = 3.5 cm
• Number of drops to form monolayer = 1 drop
• Area of monolayer

Area = xp2 = X

3.5 cm2 Area = ax = 9.62 cm 2

• Concentration of stearic acid = 0.00150 g/mL
• Volume of stearic acid in the monolayer

1 mL Volume = 1 drop X 61 = 0.0164 mL 61 drop

• Mass of stearic acid in the monolayer

mdss Concentration = ► mass = volume x concentration volume

mass = 0.0164 mL < 0.00150 9 = 2.46x10-5g

• Number of molecules in monolayer

molecules = 9.62 cm x 2. 1 molecule (1.61010) A2 1 m2 1m2 (100)2 cm 21.42X

molecules = 9.62 cm 1 molecule x = o = 4.58x1015 molecules 2.1.x10-15 cm2

• Moles of stearic acid in monolayer

mass moles = MW 2.46.2109 284 g/mol -8.66.610-8 mol

• Avogadros number

molecules Avogadro's number = moles 4.5871015 molecules 8.66.c10-8 mol

• % error

% error = [Experimental - Real 1 x 100% Real

% error = [5.29x1022 – 6.02210231 1 x 100% = 90.88% 6.02.c 1023