Question

If 125 cal are added to 89.8 g of solid iron, what is the change in temperature of the iron? The specific heat of iron is 0.11 cal g⋅°C.?

Answer 1

We know that, heat required to change temperature of material is given as, q = m $1585332139372_blob.png$ C $1585332139597_blob.png$ $1585332139532_blob.png$ T

Where, q is a heat absorbed or given out by material,  m is a mass of material , C is a specific heat capacity of material, $1585332139661_blob.png$ T is a change in temperature of material.

Given : q = 125 cal , m = 89.8 g , C = 0.11 Cal / g 0 C

Substituting given values in above relation, we get 125 cal = 89.8 g $1585332139372_blob.png$0.11 Cal / g 0 C $1585332139372_blob.png$$1585332139532_blob.png$T

$1585332139532_blob.png$T = 125 cal / 89.8 g $1585332139372_blob.png$0.11 Cal / g 0 C

$1585332139532_blob.png$T = 12.65 0 C

ANSWER : change in temperature of the iron = 13 0 C