1)
q = mc∆T
q amount of heat released it added
m is mass
c is specific heat capacity
∆T is temperature
Given that,
m = 50.0 g
c = 4.18 J/g.°C
∆T = 52.7 °C - 26.3 °C
∆T = 26.4 °C
q = 50.0 g × 4.18 J/g.°C × 26.4 °C
q = 5517.6 J
q = 5.52×10^3 J
Calculate the amount of heat (in loules) that must be added to 50.0 g of water...
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