Question

At a certain temperature, 0.680 mol SO, is placed in a 4.00 L container. 250,($) - 250,() +0,() At equilibrium, 0.120 mol O, is present. Calculate K. K-

Answer 1

The given equilibrium reaction is

         2SO3(g)                <---->     2SO2(g)       +    O2(g)

initial                0.680 mol                -                 -

change -0.240 mole            0.240 mole       0.120 mole

equil           0.440 mole               0.240 mole      0.120 mole

The equilibrium constant for the above reaction is given by

Kc = [SO2]^2 [O2]/[SO3]^2

     = (0.240/4)^2*(0.120/4)/(0.440/4)^2

     = 0.008926

Ans: Kc = 0.008926