At a certain temperature, 0.620 mol of SO3 is placed in a 4.00-L container. At equilibrium, 0.100 mol of O2 is present. Calculate Kc.
2SO3 (g) ----> 2SO2(g) + O2(g)
Kc =?
molarity of SO3 = 0.620 / 4.00 = 0.155 M
molarity of O2 = 0.100 / 4 = 0.025 M = x
substitute x value
2 SO3 <-------------------> 2SO2 + O2
0.155-2x 2x x ------------> initial
0.105 0.05 0.025 --------------> equilibrium
Kc = [SO2]^2[O2]/[SO3]^2
Kc = (0.05)^2 (0.025)/ (0.105)^2
Kc = 5.67 x 10^-3
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