At a certain temperature, 0.820 mol SO3 is placed in a 4.00 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.130 mol O2 is present. Calculate ?c.
Answer:
Explanation:
Kc is defined as the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature
Step 1: Write the balanced the chemical equation
2SO3 (g) <--------------> 2SO2 (g)+O2(g)
Step 2: Calculate the Concentrations by dividing the given moles by volume of container.
Initial SO3 = (0.820 moles / 4 litre ) = 0.205 M
as well the concentration of O2 at equilibrium = ( 0.130 moles / 4 L ) = 0.0325 M
Step 3: Write the ICE table
2SO3 (g) <--------------> 2SO2 (g) + O2(g)
Initial amount 0.205 0 0
Change amount -2x +2x +x
Equilibrium amount 0.205-2x 2x x
Since the value of O2 at equlibrium is given [O2] = 0.0325 M = [x]
hence value of x = 0.0325 M
Hence all value at equilibrium is
[SO3] = 0.205 -2x = 0.205 -(2 × 0.0325 ) =0.14
[SO2] = 2x = 2 × 0.0325 = 0.065
[O2] = x = 0.0325
Step 4: Calculate the Kc
Kc = [SO2]2 × [O2] / [SO3]2 = ( 0.065)2×(0.0325) / (0.14)2 = 7 ×10-3
At a certain temperature, 0.820 mol SO3 is placed in a 4.00 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At...
At a certain temperature, 0.820 mol SO3 is placed in a 1.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.110 mol O2 is present. Calculate ?c.
1- At a certain temperature, 0.820 mol of SO3 is placed in a 2.50-L container. 2SO3(g)---->2SO2(g)+O2(g) At equilibrium, 0.120 mol of O2 is present. Calculate Kc. 2- At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3. H2(g) + I2(g)----->2HI(g) At this temperature, 0.300 mol of H2 and 0.300 mol of I2 were placed in a 1.00-L container to react. What concentration of HI is present at equilibrium? 3-Carbon disulfide is prepared by heating sulfur and charcoal....
At a certain temperature, 0.880 mol SO3 is placed in a 2.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.110 mol O2 is present. Calculate ?c.
At a certain temperature, 0.720 mol SO3 is placed in a 5.00 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. Calculate ?c.
At a certain temperature, 0.680 mol SO3 is placed in a 4.50 L container.2SO3(g)⇌2SO2(g)+O2(g)At equilibrium, 0.110 mol O2 is present.
At a certain temperature, 0.620 mol of SO3 is placed in a 4.00-L container. At equilibrium, 0.100 mol of O2 is present. Calculate Kc. 2SO3 (g) ----> 2SO2(g) + O2(g) Kc =?
At a certain temperature, 0.720 mol of SO3 is placed in a 2.00-L container. 2SO3(g) <=> 2SO2(g) + O2(g) At equilibrium, 0.100 mol of O2 is present. Calculate Kc
At a certain temperature, 0.940 mol of SO3 is placed in a 1.5 L container. 2SO3 =2SO2 + O2. At equilibrium 0.120 mol of O2 is present. Calculate Kc
At a certain temperature 0.700mol of SO3 is placed in a 3.00L container. 2SO3(g) (forward, reverse arrows) 2SO2(g) + O2(g). At equilibrium, 0.190 mol of O2 is present. Calculate Kc.
At a certain temperature, 0.760 mol SO3is placed in a 2.50 L container.2SO3(g)⇌2SO2(g)+O2(g)At equilibrium, 0.130 mol O20.130 mol O2 is present. Calculate Kc.