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Could you please help me with the questions I got wrong? If you dont know the answer please do not comment, leave it for another expert to answer because I really need to get this done , Thank you so much ^^ There's also a guide to the calculations but i dont get it

Table view List view Sample 2 Sample 3 Table 5. Calculations for concentration of acid solution Sample 1 [1] Volume of acid (Molar mass for unknown acid: 192.140 g/mol (pending/2pts) Balanced chemical equation for neutralization of acid with NaOH TabSolution: Once you calculate the number of moles of NaOH used to neutralize the unknown solution (6.4) you need to find out tsample using the following molecular equation and mole to mole ratio. HA(aq) + NaOH(aq) → NaA(aq) + H20(1) (6.5b) 1 mol HA mo

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RE Table 5: Calculation for concentration of acid Sample Carccelation for trial lis shown below. semple-1 Calallate the molessample caclutation for sample to Moles of NaOH used molosity x volume in uter x 27.29 X10 -3 L 0.107 mol O ·00292 moll Sirxce

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