One mole of nickel at 298K at 1 atm is increased to 1000K in an isobaric process. Calculate the change of enthalpy and entropy. Also calculate the absolute values of enthalpy and entropy of the system at 1000K.
One mole of nickel at 298K at 1 atm is increased to 1000K in an isobaric...
Calculate change in entropy for 1 mole gas due to heating from 298K to 498K for the following : A) closed, monatomic gas, isochoric B) closed, monatomic ideal gas, isobaric C) closed, diatomic ideal gas, isochoric D) closed, diatomic ideal gas, isobaric
When the pressure P is constant at 1 atm, the melting point of Br_2 is T_m = 265.95 K and its boiling point is T_b = 331.85 K. Br_2 is therefore liquid at 298 K and 1 atm but it also has a finite vapor pressure hence the property of both liquid and gas Br_2 can be obtained at at 298 K and 1 atm. Using a DeHoff equation and the thermodynamic table on D2L calculate the absolute molar entropy...
One mole of a monatomic perfect gas, initially at 298 K and 1 atm, expands irreversibly and isothermally against 0.5 atm, doing 400 J of work in the process. Calculate or explain the values of DU, DH, DG, q, DSsys, DSsurr and DStot. Also, calculate the reversible work for this isothermal change of state.
please help with these Fe2O3(s) + 3H2(g) +2Fe(s) + 3H2O(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.37 moles of Fe2O3() react at standard conditions. AS system JK 2CO(g) + O2(g) +2CO2(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.54 moles of CO(g) react at standard conditions. AS system JK 2NH3(g) + 3N20(g)— 4N2(g) + 3H2O(g) AH = -879.5 kJ and AS° = 288.1 J/K The...
What is the change in volume for this reaction (ΔVR(1 bar, 298K)) at 298K and 1 bar? Are the products or reactants denser? What is the change in enthalpy for this reaction (ΔHR(1 bar, 298K)) at 298K and 1 bar? Is the reaction exothermic or endothermic? What is the change in internal energy for this reaction (ΔER(1 bar, 298K)) at 298K and 1 bar? For this reaction, under these conditions is q or w the more significant term? What is...
Calculate the entropy change for the following processes: (a) a mole of He (g) undergoes an expansion from V to 2V at 298 K (b) the temperature of one mole of CH4 (g) is increased from 298k to 325k at a constant pressure of 1 bar
1) Consider the reaction: P4O10(s) + 6H2O(l)------>4H3PO4(aq) Using standard absolute entropies at 298K, calculate the entropy change for the systemwhen 1.53 moles ofP4O10(s) react at standard conditions. S°system = J/K 1b) Consider the reaction: 2H2O2(l)--------->2H2O(l) +O2(g) Using standard absolute entropies at 298K, calculate the entropy change for the systemwhen 1.87 moles ofH2O2(l) react at standard conditions. S°system = J/K
Consider the reaction: Ca(OH)2(aq) + 2HCl(aq) +CaCl(s) + 2H2O(1) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.26 moles of Ca(OH)2(aq) react at standard conditions As system = JK Consider the reaction: 200(g) + O2(9)—*2002) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.60 moles of CO(g) react at standard conditions. ASºsystem ПІК
Consider the reaction: 2Fe(s) + 3Cl2(g)— 2FeCl3(s) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.28 moles of Fe(s) react at standard conditions. ASºsystem JK Consider the reaction: NH4Cl(aq)— »NH3(g) + HCl(aq) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.86 moles of NH4Cl(aq) react at standard conditions. ASºsystem = 1 J/K
One mole of methane gas (CH4) is heated isobarically at a pressure of 1 atm from 82.2 ° C to 211.9 ° C in a cylindrical piston device with condensed steam from saturated vapor to fully condensed at 250 ° C. a. If methane is considered an ideal gas, calculate ΔU, ΔH, ΔS, ΔG (in Joule) b. Calculate work (W) and heat involved (Q), (in Joule). c. Calculate the change in environment, and the total entropy generated by this process...